1.
Let \(\varphi:G \to H\) be a group homomorphism with kernel \(K\text{.}\) Prove that \(\varphi\) is injective (i.e., one-to-one) if and only if \(K = \{e\}\) (that is, the only element in the kernel is the identity).
Hint.
The definition of a function being injective is that every element in the codomain is the image of at most one element of the domain. In other words, if \(g_1 \ne g_2\) are distinct elements of the domain, then \(\varphi(g_1) \ne \varphi(g_2)\) (that is, different inputs must go to different outputs).
In practice, it is easier to use the contrapositive of this: \(\varphi\) is injective precisely when if \(\varphi(g_1) = \varphi(g_2)\text{,}\) then \(g_1 = g_2\text{.}\) Using this βdefinitionβ of injective is what you want to do for this exercise.
